43. Solving a chemistry problem
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368. The reaction is expressed by the schemes:
CrCl3 Br2 KOH = K2CrO4 KBr H2O KCl,
KMnO4 H2S H2SO4 = K2SO4 MnSO4 S H2O.
Write electronic equations. Arrange the coefficients in the reaction equations. For each reaction, indicate which substance is the oxidizing agent, which is the reducing agent; which substance is oxidized and which is reduced.
CrCl3 Br2 KOH = K2CrO4 KBr H2O KCl,
KMnO4 H2S H2SO4 = K2SO4 MnSO4 S H2O.
Write electronic equations. Arrange the coefficients in the reaction equations. For each reaction, indicate which substance is the oxidizing agent, which is the reducing agent; which substance is oxidized and which is reduced.
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