43. Solving a chemistry problem
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363. The reaction is expressed by the schemes:
FeSO4 KClO3 H2SO4 = Fe2(SO4)3 KCl H2O,
Cu H2SO4,conc = CuSO4 SO2 H2O.
Write electronic equations. Arrange the coefficients in the reaction equations. For each reaction, indicate which substance is the oxidizing agent, which is the reducing agent; which substance is oxidized and which is reduced.
FeSO4 KClO3 H2SO4 = Fe2(SO4)3 KCl H2O,
Cu H2SO4,conc = CuSO4 SO2 H2O.
Write electronic equations. Arrange the coefficients in the reaction equations. For each reaction, indicate which substance is the oxidizing agent, which is the reducing agent; which substance is oxidized and which is reduced.
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