58. Solving a chemistry problem

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58. Solving a chemistry problem

Product Description

2. Determine the molar mass of the equivalent of the oxidizing agent and reducing agent in the reaction:
MnO2(tv) 2I– 4H = Mn2 I2 2H2O

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If you do not open the file - install the RAR archiver. Inside the archive you will find a solution in Word format.
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