Task 44 Closed tank with oil
📂 For Education Students
👤 Pingvin78
Product Description
Task 44 A closed tank with oil p = 900 kg / m3 is divided by a flat partition having a square flap with side a = 1m. The pressure above the oil in the left part of the tank is determined by the reading of the pressure gauge Rm = 20 kPa, and in the right – by the reading of the vacuum gauge Rvak = 30 kPa.
Determine the magnitude of the resultant force of oil pressure on the square flap and the displacement of its center of pressure relative to the center of gravity of the site.
Determine the magnitude of the resultant force of oil pressure on the square flap and the displacement of its center of pressure relative to the center of gravity of the site.
Additional Information
The solution is made in the Word editor with a set of formulas. The task is performed as part of the control work on hydraulics. After payment, we guarantee to receive a file with this task. It is possible to perform according to your tasks.
Related Products
Solution of the C2 Option 04 Dievskaya VA Malyshev IA
Seller: TerMaster
Solution of the C2 Option 05 Dievskaya VA Malyshev IA
Seller: TerMaster
Dievsky V.A. - Solution of task C2 variant 22 (C2-22)
Seller: Михаил_Перович
Solution K5 B04 termehu of Reshebnik Yablonsky AA 1978
Seller: TerMaster
Solution of the K2 version 07 Dievskaya VA Malyshev IA
Seller: TerMaster
Solution of the C2 Option 14 Dievskaya VA Malyshev IA
Seller: TerMaster
Solution of the C2 Option 08 Dievskaya VA Malyshev IA
Seller: TerMaster
Conflict law test Synergy answers 90/100 points
Seller: sinergey
More from this Seller
Task 1.3
Test section
Tasks on hydraulics miscellaneous 3
Test section
Tasks on hydraulics miscellaneous 7
Test section
Tasks on hydraulics miscellaneous 9
Test section