143. Solving a chemistry problem
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6.33. Using the benzene adsorption isotherm, determine the specific surface area of the adsorbent (T = 293 K, S0 = 49 * 10–20 m2):
P / Ps 0.06 0.12 0.20 0.30 0.40 0.50
A, mol / kg 0.40 0.55 0.68 0.83 0.98 1.20
P / Ps 0.06 0.12 0.20 0.30 0.40 0.50
A, mol / kg 0.40 0.55 0.68 0.83 0.98 1.20
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