Solving a problem in physics section 39 paragraph 2 el
📂 Physics
👤 Massimo86
Product Description
2. By alternately connecting the power EMF two electric heaters with a resistance R1 = 3 ohms and R2 = 48 ohms are given the same power, P = 1,2 kW. Determine the strength of the current Isc short-circuit power.
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Detailed solution. Decorated in Microsoft Word 2003. (Target decided to use formula editor)
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Product: Solving a problem in physics section 39 paragraph 2 el
1/7/2026
Большое спасибо, всё отлично!
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